1조, 2.2절

1975 days 전, qogustlr7 작성

P(x) = 0.002*x + 0.004*x^2 
       
P(500) 
       
1001.00000000000
1001.00000000000
P(2000) 
       
16004.0000000000
16004.0000000000
F(x)=x^2+1/3*x-1 
       
F(-2.73) 
       
5.54290000000000
5.54290000000000
F(-x) 
       
x^2 - 1/3*x - 1
x^2 - 1/3*x - 1
1/F(x)-1 
       
3/(3*x^2 + x - 3) - 1
3/(3*x^2 + x - 3) - 1