4조-2.6-과제 조주법

2018 days 전, whwnqjq119 작성

2.6절 5-1

f(x)=(x+2)^2 plot(f(x), (x, -5, 3), ymax=10, ymin=-10, color='red')+point((-2, 0), color='red') 
       

2.6절 5-2

f(x)=(x+3)^2-4 plot(f(x), (x, -7, 2), ymax=10, ymin=-8)+point((-3, -4), color='red') 
       

2.6절 5-3

f(x)=-2*(x+3)^2+3 plot(f(x), (x,-6,2), ymax=5, ymin=-20,color='red')+point((-3, 3), color='red') 
       

2.6절 5-4

f(x)=x^2+6*x+5 plot(f(x), (x, -6, 1), ymin=-8,ymax=10,color='red')+point((-3, -4), color='red') 
       

2.6절 5-5

f(x)=-x^2-x+2 plot(f(x), (x,-3,2),ymax=5,ymin=-10)+point((-(1/2), 9/4), color='red') 
       

2.6절 5-6

f(x)=-2*x^2-4*x-2 plot(f(x), (x,-2,1),ymax=2,ymin=-10)+point((-1, 0), color='red') 
       

2.6절 5-7

f(x)=(1/2)*x^2+2*x+4 plot(f(x), (x,-4,1), ymin=1,ymax=6)+point((-2, 2), color='red') 
       

2.6절 5-8

f(x)=-2*x^2+2*x-(5/2) plot(f(x), (x,-2,4),ymax=0,ymin=-6)+point((1/2, -2), color='red')