# 선형대수응용_HW_W2

## 679 days 전, jongha4886 작성

A = matrix([[2,5,0,4,3,-3,1], [2,-1,-4,-3,6,0,-2], [0,-2,2,6,4,5,1], [2,4,-2,1,5,0,6], [-3,3,-4,-5,4,2,5], [-1,-8,10,6,9,3,-5], [6,2,8,-6,-2,-10,4]]) b = vector([1,-1,0,3,2,5,4]) c = A.augment(b).rref() print "Gauss-Jordan 소거법을 적용해 구한 RREF는 ", c print "" print "그 결과 해는, x =", A.solve_right(b), "입니다."
 Gauss-Jordan 소거법을 적용해 구한 RREF는 [ 1 0 0 0 0 0 0 -139987/105332] [ 0 1 0 0 0 0 0 -42562/26333] [ 0 0 1 0 0 0 0 -115609/210664] [ 0 0 0 1 0 0 0 20202/26333] [ 0 0 0 0 1 0 0 49015/105332] [ 0 0 0 0 0 1 0 -52252/26333] [ 0 0 0 0 0 0 1 139245/105332] 그 결과 해는, x = (-139987/105332, -42562/26333, -115609/210664, 20202/26333, 49015/105332, -52252/26333, 139245/105332) 입니다. Gauss-Jordan 소거법을 적용해 구한 RREF는 [ 1 0 0 0 0 0 0 -139987/105332] [ 0 1 0 0 0 0 0 -42562/26333] [ 0 0 1 0 0 0 0 -115609/210664] [ 0 0 0 1 0 0 0 20202/26333] [ 0 0 0 0 1 0 0 49015/105332] [ 0 0 0 0 0 1 0 -52252/26333] [ 0 0 0 0 0 0 1 139245/105332] 그 결과 해는, x = (-139987/105332, -42562/26333, -115609/210664, 20202/26333, 49015/105332, -52252/26333, 139245/105332) 입니다.